In Appian's index function, what happens if the requested index is out of bounds?

In Appian's index function, what happens if the requested index is out of bounds?

• A. The function returns the default value provided
• B. The function throws an error
• C. The function returns null
• D. The function cycles to the start of the array

Answer: (A)

The function is designed to safely fetch an element by position from a list and, when that position doesn’t exist, return a fallback value you provide. If the requested index is out of bounds, it returns the default value you pass as the third argument instead of causing an error. This makes dynamic or uncertain list access robust, because you always get something predictable rather than an exception. If the index is valid, you still get the actual element at that position. It doesn’t wrap around to the start or fail with an error, which is why supplying a default value is the best approach for out-of-range access.

The function is designed to safely fetch an element by position from a list and, when that position doesn’t exist, return a fallback value you provide. If the requested index is out of bounds, it returns the default value you pass as the third argument instead of causing an error. This makes dynamic or uncertain list access robust, because you always get something predictable rather than an exception. If the index is valid, you still get the actual element at that position. It doesn’t wrap around to the start or fail with an error, which is why supplying a default value is the best approach for out-of-range access.